10x^2+3y*5/5x

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Solution for 10x^2+3y*5/5x equation:


x in (-oo:+oo)

10*x^2+x*((3*5*y)/5) = 0

10*x^2+3*x*y = 0

DELTA = (3*y)^2-(0*4*10)

DELTA = 9*y^2

9*y^2 = 0

9*y^2 = 0 // : 9

y^2 = 0

y = 0

DELTA = 0 <=> t_1 = 0

x = (-(3*y))/(2*10) i y = 0

x = (-3*y)/20 i y = 0

( x = ((9*y^2)^(1/2)-(3*y))/(2*10) or x = (-(3*y)-(9*y^2)^(1/2))/(2*10) ) i y > 0

( x = 0 or x = (-3*y)/10 ) i y > 0

y+0 > 0

y > 0

y+0 > 0 // - 0

y > 0

x in { (-3*y)/20, 0, (-3*y)/10 }

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